Try this beautiful problem from the Pre-RMO, 2019 based on Circles,Triangle and largest integer.
Let ABC be a triangle with sides 51, 52, 53. Let D denote the incircle of triangle ABC. Draw tangents to D which are parallel to the sides ABC. let \(r_1\). \(r_2\), \(r_3\) be the inradii of the three corner triangles so formed, find the largest integer that does not exceed \(r_1+r_2+r_3\).
Circles
Triangle
Largest Integers
But try the problem first...
Answer: is 15.
PRMO, 2019, Question 28
Geometry Vol I to IV by Hall and Stevens
First hint
Let PQ be one of tangents parallel to BC and meet sides AB and AC at P and Q let PQ=x and BC=51
Second Hint
triangle ABC similar with triangle APQ then\(\frac{x}{a}=\frac{r_1}{r}=\frac{s-a}{s}\) which is in same way for \(\frac{y}{b}\) and \(\frac{z}{c}\) then \(\frac{r_1+r_2+r_3}{r}\)=\(\frac{x}{a}+\frac{y}{b}+\frac{z}{c}\)=3-2=1
Final Step
then \(r_1+r_2+r_3\)=r and r by given condition of question =\((\frac{s(s-a)(s-b)(s-c)}{s})^\frac{1}{2}\)=\((\frac{78(78-51)(78-52)(78-53)}{78})^\frac{1}{2}\)=15.
Try this beautiful problem from the Pre-RMO, 2019 based on Circles,Triangle and largest integer.
Let ABC be a triangle with sides 51, 52, 53. Let D denote the incircle of triangle ABC. Draw tangents to D which are parallel to the sides ABC. let \(r_1\). \(r_2\), \(r_3\) be the inradii of the three corner triangles so formed, find the largest integer that does not exceed \(r_1+r_2+r_3\).
Circles
Triangle
Largest Integers
But try the problem first...
Answer: is 15.
PRMO, 2019, Question 28
Geometry Vol I to IV by Hall and Stevens
First hint
Let PQ be one of tangents parallel to BC and meet sides AB and AC at P and Q let PQ=x and BC=51
Second Hint
triangle ABC similar with triangle APQ then\(\frac{x}{a}=\frac{r_1}{r}=\frac{s-a}{s}\) which is in same way for \(\frac{y}{b}\) and \(\frac{z}{c}\) then \(\frac{r_1+r_2+r_3}{r}\)=\(\frac{x}{a}+\frac{y}{b}+\frac{z}{c}\)=3-2=1
Final Step
then \(r_1+r_2+r_3\)=r and r by given condition of question =\((\frac{s(s-a)(s-b)(s-c)}{s})^\frac{1}{2}\)=\((\frac{78(78-51)(78-52)(78-53)}{78})^\frac{1}{2}\)=15.
