Akash Singha Roy

Problem :

Let be positive integers such that for all where is constant. If then the value of is

(A)

(B)

(C)

(D)

Solution:

We have

for all

Putting in the above relation we obtain,

This gives,

and

Thus,

Now, since

therefore we have,

which, in turn, gives,

.

Therefore, option (B) is the correct option.