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(12) positive charges of magnitude (q) are placed on a circle of radius (R) in a manner that they are equally spaced. A charge (Q) is placed at the centre. If one of the charges (q) is removed, then the force on (Q) is
(A) zero
(B)$$\frac{qQ}{4\pi\epsilon_0R^2}$$ away from the position of the removed charge

(C) $$\frac{11qQ}{4\pi\epsilon_0R^2}$$ away from the position of the removed charge
(D)
$$\frac{qQ}{4\pi\epsilon_0R^2}$$ towards from the position of the removed charge

Discussion:

If one of the charges is removed, then net force on Q is $$\frac{qQ}{4\pi\epsilon_0R^2}$$ towards the position of removed charge