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Removed Charge (Kvpy ’10)

\(12\) positive charges of magnitude \(q\) are placed on a circle of radius \(R\) in a manner that they are equally spaced. A charge \(Q\) is placed at the centre. If one of the charges \(q\) is removed, then the force on \(Q\) is
(A) zero
(B)$$ \frac{qQ}{4\pi\epsilon_0R^2}$$ away from the position of the removed charge

(C) $$ \frac{11qQ}{4\pi\epsilon_0R^2}$$ away from the position of the removed charge
(D)
$$ \frac{qQ}{4\pi\epsilon_0R^2}$$ towards from the position of the removed charge

Discussion:

If one of the charges is removed, then net force on Q is $$ \frac{qQ}{4\pi\epsilon_0R^2}$$ towards the position of removed charge

October 20, 2017

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