Ratio Problem from AMC 10B – 2020 – Problem No.3

This one is an easy sum to solve but those who are confused right now can use the first hint :

The ratio of w : x = 4 : 3 ; so we can write it \(\frac {w}{x} = \frac {4}{3}\). Similarly we can do it for the other given ratios. Try to do it……

I think you have already got the answer . If not then try this out …..

z : x = 1 : 6 i.e \(\frac {z}{x} = \frac {1}{6} \)

y : z = 3 : 2 i.e \(\frac {y}{z} = \frac {3}{2}\)

This hint is the final hint as already mentioned in header :

Lets multiply each ratios :

\(\frac {w}{x} \times \frac {x}{z} \times \frac {z}{y} = \frac {4}{3} \times 6 \times \frac {2}{3} \)

After canceling out all the similar terms \(\frac {w}{y} = \frac {16}{3}\)