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Explore the Back-StoryTry this triangle area Problem based on Similarity from PRMO - 2017.

Consider the areas of the four triangles obtained by drawing the diagonals $A C$ and $B D$ of a trapezium $A B C D$. The product of these areas, taken two at time, are computed. If among the six products so obtained, two products are 1296 and 576 , determine the square root of the maximum possible area of the trapezium to the nearest integer.

Similar Triangles

Area of Triangles

Finding the maximum area

Suggested Reading

Source of the Problem

Answer

Challenge and Trill of Pre College Mathematics

PRMO 2017 Problem 30

The maximum possible area is 13

Hint 1

Hint 2

Hint 3

Let us denote by $\triangle ABC$ the area of triangle ABC.

Lets the point of intersection of the diagonals of the trapezium be O

Hence $\frac{\triangle ABO}{\triangle CDO}$ = $\frac{{AB}^{2}}{{CD}^{2}}$

$\triangle ADO$=$\triangle BCO$

$\frac{\triangle ABO}{\triangle ADO} $= $\frac{BO}{OD}$=$\frac{AB}{CD}$

If$y$=$\frac{AB}{CD}$ and $\triangle ABO$ = $x$ then

$\triangle AOB$, $\triangle BOC$, $\triangle COD$, $\triangle AOD$ = $x$, $xy$, $x{y}^{2}$, $xy$

Then consider different cases and find out the different values of $x$, $y$ and the corresponding values of the area of the triangle and find the maximum of them.

Try this triangle area Problem based on Similarity from PRMO - 2017.

Consider the areas of the four triangles obtained by drawing the diagonals $A C$ and $B D$ of a trapezium $A B C D$. The product of these areas, taken two at time, are computed. If among the six products so obtained, two products are 1296 and 576 , determine the square root of the maximum possible area of the trapezium to the nearest integer.

Similar Triangles

Area of Triangles

Finding the maximum area

Suggested Reading

Source of the Problem

Answer

Challenge and Trill of Pre College Mathematics

PRMO 2017 Problem 30

The maximum possible area is 13

Hint 1

Hint 2

Hint 3

Let us denote by $\triangle ABC$ the area of triangle ABC.

Lets the point of intersection of the diagonals of the trapezium be O

Hence $\frac{\triangle ABO}{\triangle CDO}$ = $\frac{{AB}^{2}}{{CD}^{2}}$

$\triangle ADO$=$\triangle BCO$

$\frac{\triangle ABO}{\triangle ADO} $= $\frac{BO}{OD}$=$\frac{AB}{CD}$

If$y$=$\frac{AB}{CD}$ and $\triangle ABO$ = $x$ then

$\triangle AOB$, $\triangle BOC$, $\triangle COD$, $\triangle AOD$ = $x$, $xy$, $x{y}^{2}$, $xy$

Then consider different cases and find out the different values of $x$, $y$ and the corresponding values of the area of the triangle and find the maximum of them.

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