# Understand the problem

A sequence of natural numbers is constructed by listing the first , then skipping one, listing the next , skipping , listing , skipping , and, on the th iteration, listing and skipping . The sequence begins . What is the th number in the sequence ?

##### Source of the problem

##### Topic

Number Theory, Sequences

##### Difficulty Level

7/10

##### Suggested Book

# Start with hints

Stuck…? Well, don’t worry. *The key to solving this problem is not thinking too much about the skips.* We can start with natural numbers, from **1** to **500,000**. So, a useful strategy could be to find how many numbers we have actually skipped, **n** and then add them back accordingly. So, now could you take things on from here ?

If you’re a tad bit doubtful of where we’re heading even now, well no problem. Clearly, we can say ** 999.(1000) / 2 < 500,000 < 1000.(1001) / 2** So, now can you find out how many blocks of gaps we have in the sequence ?

Now see, finding the blocks of gaps easy ! There’s just one small thing you would have to recall. **We began the count from 4…so now, the number of skipped blocks in the sequence = 999 – 3 = 996.** Now to find n, from the number of blocks , we have = **(996.997) / 2 = 496,506** This stands for the number of numbers we skipped. Now concluding this is fairly easy…could you try that out yourself ? * *

What remains for us to do is to add back those skipped numbers to the count, **500,000** to obtain the final answer. That gives us = **500000 +496506 = 996506**

And we are done !

# Watch video

# Connected Program at Cheenta

#### Math Olympiad Program

Math Olympiad is the greatest and most challenging academic contest for school students. Brilliant school students from over 100 countries participate in it every year. Cheenta works with small groups of gifted students through an intense training program. It is a deeply personalized journey toward intellectual prowess and technical sophistication.

Google