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Problem
The number of different factors of 1800 equals:
(A) 12; (B) 210; (C) 36; (D) 18;

Discussion:
We may factor 1800 as $2^3 \times 3^2 \times 5^2$
Then the number of factors is: $(3+1) \times (2+1) \times (2+1) = 36$