Try this TOMATO problem from I.S.I. B.Stat Entrance Objective Problem based on Number of divisors and Integer.
The smallest positive integer n with 24 divisors (where 1 and n are also considered divisors of n) is
But try the problem first...
B.Stat Objective Question 83
Challenges and Thrills of Pre-College Mathematics by University Press
number of divisors of 420=(2+1)(1+1)(1+1)(1+1)=24
number of divisors of 240=(4+1)(1+1)(1+1)=20
number of divisors of 360=(3+1)(2+1)(1+1)=24 and number of divisors of 480=(5+1)(1+1)(1+1)=24 then required number =360.
From the video below, let's learn from Dr. Ashani Dasgupta (a Ph.D. in Mathematics from the University of Milwaukee-Wisconsin and Founder-Faculty of Cheenta) how you can shape your career in Mathematics and pursue it after 12th in India and Abroad. These are some of the key questions that we are discussing here: