## Problem – Hidden Faces of Dice (AMC Middle Primary)

Let’s solve a problem based on missing numbers from the hidden faces of dice.

*Three standard dice are sitting next to each other as shown in the diagram. There are 7 faces visible. How many dots are hidden on the other 11 sides?*

- 26
- 36
- 41
- 63

**Key Concepts**

Dice Problem

**Missing Values**

Arithmetic

## Check the Answer

But try the problem first…

Answer: 41

Australian Mathematics Competition – Middle Primary Division

Basic Arithmetic by Robert Moon

## Try with Hints

First Hint

*This one is very easy but if you really need any hints at first take a dice and try to understand the number of dots in each sides .*

Second Hint

*So for first dice : we can see 4,5 and 1. So the no of dots which are not seen 6,2 and 3 *

*For Second Dice : The visible dots are 2 and 6 . So the dots in sides which are not visible are 4,3,1 and 5.*

*For Third Dice : The Visible dots are 3 and 1 .So the dots which are not visible 2,4,5 and 6.*

Final Hint

*I think you have already got the answer but if you really need this last step :*

*Now add all the number of dots from the invisible sides:*

*2+4+5+6+4+3+1+5+6+2+3 = 41 .*

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