Math Kangaroo (Benjamin) 2016 | Problem 20 | Algebra

Try this Problem based on Algebra from Math Kangaroo (Benjamin) 2016 Problem 20

Equation Solving | Math Kangaroo (Benjamin) 2016 | Problem 20

Luigi owns a few square tables and some chairs for his little restaurant. If he sets out his tables individually with 4 chairs each, then he is 6 chairs short. If he always puts two tables together to create a bigger table with 6 chairs, then he has 4 chairs left over.
How many tables does Luigi have?

Key Concepts

Algebra

Arithmetic

Equation Solving

Suggested Book | Source | Answer

Try with Hints

Hint 1

Hint 2

Hint 3

Hint 4

Hint 5

Let us assume the number of tables and chairs are $x, y$ respectively.

Let's follow the given condition and construct the equations.

For the first case if he set table individually with 4 chairs each then he is 6 chairs short.

So, $4x-6=y$.

Now if he put two tables together with 6 chairs each, then he has 4 chairs left over.

So, $6\frac{x}{2}+4=y$.

Comparing the equation of hint 3 and hint 4 we get,

$4x-6= 3x+4$

So, $ x=10$

Hence the answer is $10$.

Equation Solving | Math Kangaroo (Benjamin) 2016 | Problem 20

Luigi owns a few square tables and some chairs for his little restaurant. If he sets out his tables individually with 4 chairs each, then he is 6 chairs short. If he always puts two tables together to create a bigger table with 6 chairs, then he has 4 chairs left over.
How many tables does Luigi have?