This is a problem from ISI MStat 2019 PSA Problem 16 based on calculating area bounded by the curve.
The functions are given by
and
What is the area enclosed between the graphs of
and
Integration
Graph of a function
Answer: is (A)
ISI MStat 2019 PSA Problem 16
Introduction to Real Analysis by Bertle Sherbert
Inverse of a function is basically reflection about y=x line .
So , we can get and
from
and
respectively by replacing x by y and y by x .
Let's draw the curves .
This is graph of inverses of f and g when they are defined in . But in our problem we should consider one positive x axis and y axis .
Therefore area of the curve bounded by the graphs of and
is
= 1/8 .
This is a problem from ISI MStat 2019 PSA Problem 16 based on calculating area bounded by the curve.
The functions are given by
and
What is the area enclosed between the graphs of
and
Integration
Graph of a function
Answer: is (A)
ISI MStat 2019 PSA Problem 16
Introduction to Real Analysis by Bertle Sherbert
Inverse of a function is basically reflection about y=x line .
So , we can get and
from
and
respectively by replacing x by y and y by x .
Let's draw the curves .
This is graph of inverses of f and g when they are defined in . But in our problem we should consider one positive x axis and y axis .
Therefore area of the curve bounded by the graphs of and
is
= 1/8 .