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This is a problem from ISI MStat 2019 PSA Problem 16 based on calculating area bounded by the curve.

The functions are given by and What is the area enclosed between the graphs of and

- (A) 1/8
- (B) 1/4
- (C)5/12
- (D) 7/24

Integration

Graph of a function

Answer: is (A)

ISI MStat 2019 PSA Problem 16

Introduction to Real Analysis by Bertle Sherbert

Inverse of a function is basically reflection about y=x line .

So , we can get and from and respectively by replacing x by y and y by x .

Let's draw the curves .

This is graph of inverses of f and g when they are defined in . But in our problem we should consider one positive x axis and y axis .

Therefore area of the curve bounded by the graphs of and is = 1/8 .

This is a problem from ISI MStat 2019 PSA Problem 16 based on calculating area bounded by the curve.

The functions are given by and What is the area enclosed between the graphs of and

- (A) 1/8
- (B) 1/4
- (C)5/12
- (D) 7/24

Integration

Graph of a function

Answer: is (A)

ISI MStat 2019 PSA Problem 16

Introduction to Real Analysis by Bertle Sherbert

Inverse of a function is basically reflection about y=x line .

So , we can get and from and respectively by replacing x by y and y by x .

Let's draw the curves .

This is graph of inverses of f and g when they are defined in . But in our problem we should consider one positive x axis and y axis .

Therefore area of the curve bounded by the graphs of and is = 1/8 .

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