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# ISI MStat 2019 PSA Problem 16 | Area bounded by the curve This is a problem from ISI MStat 2019 PSA Problem 16 based on calculating area bounded by the curve.

## Area bounded by the curve - ISI MStat 2018 PSA Problem 16

The functions are given by and What is the area enclosed between the graphs of and • (A) 1/8
• (B) 1/4
• (C)5/12
• (D) 7/24

### Key Concepts

Integration

Graph of a function

ISI MStat 2019 PSA Problem 16

Introduction to Real Analysis by Bertle Sherbert

## Try with Hints

Inverse of a function is basically reflection about y=x line .

So , we can get and from and respectively by replacing x by y and y by x .

Let's draw the curves .

This is graph of inverses of f and g when they are defined in . But in our problem we should consider one positive x axis and y axis .

Therefore area of the curve bounded by the graphs of and is = 1/8 .

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This is a problem from ISI MStat 2019 PSA Problem 16 based on calculating area bounded by the curve.

## Area bounded by the curve - ISI MStat 2018 PSA Problem 16

The functions are given by and What is the area enclosed between the graphs of and • (A) 1/8
• (B) 1/4
• (C)5/12
• (D) 7/24

### Key Concepts

Integration

Graph of a function

ISI MStat 2019 PSA Problem 16

Introduction to Real Analysis by Bertle Sherbert

## Try with Hints

Inverse of a function is basically reflection about y=x line .

So , we can get and from and respectively by replacing x by y and y by x .

Let's draw the curves .

This is graph of inverses of f and g when they are defined in . But in our problem we should consider one positive x axis and y axis .

Therefore area of the curve bounded by the graphs of and is = 1/8 .

## Subscribe to Cheenta at Youtube

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