How can you roll a dice by tossing a coin? Can you use your probability knowledge? Use your conditioning skills.
Suppose, you have gone to a picnic with your friends. You have planned to play the physical version of the Snake and Ladder game. You found out that you have lost your dice.
The shit just became real!
Now, you have an unbiased coin in your wallet / purse. You know Probability.
starts playing in the background. :p
Ofcourse, you know chances better than others. :3
Take a coin.
Toss it 3 times. Record the outcomes.
HHH = Number 1
HHT = Number 2
HTH = Number 3
HTT = Number 4
THH = Number 5
THT = Number 6
TTH = Reject it, don't ccount the toss and toss again
TTT = Reject it, don't ccount the toss and toss again
Voila done!
What is the probability of HHH in this experiment?
Let X be the outcome in the restricted experiment as shown.
How is this experiment is different from the actual experiment?
This experiment is conditioning on the event A = {HHH, HHT, HTH, HTT, THH, THT}.
\(P( X = HHH) = P (X = HHH | X \in A ) = \frac{P (X = HHH)}{P (X \in A)} = \frac{1}{6}\)
Beautiful right?
Can you generalize this idea?
Books for ISI MStat Entrance Exam
How to Prepare for ISI MStat Entrance Exam
ISI MStat and IIT JAM Stat Problems and Solutions
How can you roll a dice by tossing a coin? Can you use your probability knowledge? Use your conditioning skills.
Suppose, you have gone to a picnic with your friends. You have planned to play the physical version of the Snake and Ladder game. You found out that you have lost your dice.
The shit just became real!
Now, you have an unbiased coin in your wallet / purse. You know Probability.
starts playing in the background. :p
Ofcourse, you know chances better than others. :3
Take a coin.
Toss it 3 times. Record the outcomes.
HHH = Number 1
HHT = Number 2
HTH = Number 3
HTT = Number 4
THH = Number 5
THT = Number 6
TTH = Reject it, don't ccount the toss and toss again
TTT = Reject it, don't ccount the toss and toss again
Voila done!
What is the probability of HHH in this experiment?
Let X be the outcome in the restricted experiment as shown.
How is this experiment is different from the actual experiment?
This experiment is conditioning on the event A = {HHH, HHT, HTH, HTT, THH, THT}.
\(P( X = HHH) = P (X = HHH | X \in A ) = \frac{P (X = HHH)}{P (X \in A)} = \frac{1}{6}\)
Beautiful right?
Can you generalize this idea?
Books for ISI MStat Entrance Exam
How to Prepare for ISI MStat Entrance Exam
ISI MStat and IIT JAM Stat Problems and Solutions
nice way!!!!!!!!!!!!!!!!