Try this beautiful problem on Graph in Calculus, useful for ISI B.Stat Entrance.
Graph in Calculus | ISI B.Stat Entrance | Problem 699
The adjoining figure is the graph of
- (a) \(y = 2e^x\)
- (b) \(y = 2e^-x\)
- (c) \(y = e^x + e^-x\)
- (d) \(y = e^x – e^-x + 2\)
Check the Answer
But try the problem first…
TOMATO, Problem 699
Challenges and Thrills in Pre College Mathematics
Try with Hints
At first we have to check all the options…..
- For \(y = 2e^x\), this is not possibe because \(y = 2e^x\) expression represent only positive side’s of x axis
- For \(y = 2e^-x\),This expression also represents one side of x-axis
- For \(y = e^x + e^-x\).This expression represents both sides of the x-axise.as we put \(x=0\) then \(y=2\) i.e the curve not starts from the origin
- \(y = e^x – e^-x + 2\), this expression also represents both sides of the x-axis
Can you now finish the problem ……….
Therefore ,the correct ans is (c)
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