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Try this beautiful problem on Graph in Calculus, useful for ISI B.Stat Entrance.

## Graph in Calculus | ISI B.Stat Entrance | Problem 699

The adjoining figure is the graph of

- (a) \(y = 2e^x\)
- (b) \(y = 2e^-x\)
- (c) \(y = e^x + e^-x\)
- (d) \(y = e^x – e^-x + 2\)

**Key Concepts**

Calculus

Graph

Functions

## Check the Answer

But try the problem first…

Answer: (C)

Source

Suggested Reading

TOMATO, Problem 699

Challenges and Thrills in Pre College Mathematics

## Try with Hints

First hint

At first we have to check all the options…..

- For \(y = 2e^x\), this is not possibe because \(y = 2e^x\) expression represent only positive side’s of x axis
- For \(y = 2e^-x\),This expression also represents one side of x-axis
- For \(y = e^x + e^-x\).This expression represents both sides of the x-axise.as we put \(x=0\) then \(y=2\) i.e the curve not starts from the origin
- \(y = e^x – e^-x + 2\), this expression also represents both sides of the x-axis

Can you now finish the problem ……….

Final Step

Therefore ,the correct ans is (c)

## Other useful links

- https://www.cheenta.com/graphs-in-calculus-isi-b-stat-objective-problem-698/
- https://www.youtube.com/watch?v=uApjRLII6YI

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