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# Graph in Calculus | ISI-B.stat | Objective Problem 699

Try this beautiful problem on Graph in Calculus, useful for ISI B.Stat Entrance.

## Graph in Calculus | ISI B.Stat Entrance | Problem 699

The adjoining figure is the graph of

• (a) $y = 2e^x$
• (b) $y = 2e^-x$
• (c) $y = e^x + e^-x$
• (d) $y = e^x – e^-x + 2$

Calculus

Graph

Functions

## Check the Answer

Answer: (C)

TOMATO, Problem 699

Challenges and Thrills in Pre College Mathematics

## Try with Hints

At first we have to check all the options.....

1. For $y = 2e^x$, this is not possibe because $y = 2e^x$ expression represent only positive side's of x axis
2. For $y = 2e^-x$,This expression also represents one side of x-axis
3. For $y = e^x + e^-x$.This expression represents both sides of the x-axise.as we put $x=0$ then $y=2$ i.e the curve not starts from the origin
4. $y = e^x – e^-x + 2$, this expression also represents both sides of the x-axis

Can you now finish the problem ..........

Therefore ,the correct ans is (c)

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