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Try this beautiful problem on Graph in Calculus, useful for ISI B.Stat Entrance.

Graph in Calculus | ISI B.Stat Entrance | Problem 699

The adjoining figure is the graph of

• (a) $y = 2e^x$
• (b) $y = 2e^-x$
• (c) $y = e^x + e^-x$
• (d) $y = e^x – e^-x + 2$

Key Concepts

Calculus

Graph

Functions

But try the problem first…

Source

TOMATO, Problem 699

Challenges and Thrills in Pre College Mathematics

Try with Hints

First hint

At first we have to check all the options…..

1. For $y = 2e^x$, this is not possibe because $y = 2e^x$ expression represent only positive side’s of x axis
2. For $y = 2e^-x$,This expression also represents one side of x-axis
3. For $y = e^x + e^-x$.This expression represents both sides of the x-axise.as we put $x=0$ then $y=2$ i.e the curve not starts from the origin
4. $y = e^x – e^-x + 2$, this expression also represents both sides of the x-axis

Can you now finish the problem ……….

Final Step

Therefore ,the correct ans is (c)