Try this beautiful problem from PRMO, 2019 based on Good numbers.
A natural number \(k > \) is called good if there exist natural numbers
\(a_1 < a_2 < ………. < a_k\)
\(\frac{1}{\sqrt a_1} +\frac{1}{\sqrt a_2}+................... +\frac{1}{\sqrt a_k}=1\)
Let \(f(n)\) be the sum of the first \(n\) good numbers, \(n \geq 1\). Find the sum of all values of \(n\) for which
\(f(n + 5)/f(n)\) is an integer.
Number theory
Good number
Integer
But try the problem first...
Answer:\(18\)
PRMO-2019, Problem 12
Pre College Mathematics
First hint
A number n is called a good number if It is a square free number.
Let \(a_1 ={A_1}^2\),\(a_2={A_2}^2\),..................\(a_k={A_k}^2\)
we have to check if it is possible for distinct natural number \(A_1, A_2………….A_k\) to satisfy,
\(\frac{1}{A_1}+\frac{1}{A_2}+...........+\frac{1}{A_k}=1\)
Can you now finish the problem ..........
Second Hint
For \(k = 2\); it is obvious that there do not exist distinct\( A_1, A_2\), such that \(\frac{1}{A_1}+\frac{1}{A_2}=1 \Rightarrow 2\) is not a good number
For \(k = 3\); we have \(\frac{1}{2} +\frac{1}{3}+\frac{1}{6}=1 \Rightarrow 3\) is a good number.
\(\frac{1}{2}+\frac{1}{2}\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=1\) \(\Rightarrow 4\) is a good number
Let \(k\) wil be a good numbers for all \(k \geq 3\)
\(f(n) = 3 + 4 +… n\) terms =\(\frac{n(n + 5)}{2}\)
\(f(n + 5) =\frac{(n + 5)(n +10)}{2}\)
\(\frac{f(n+5}{f(n)}=\frac{n+10}{n}=1+\frac{10}{n}\)
Can you finish the problem........
Final Step
Therefore the integer for n = \(1\), \(2\), \(5\) and \(10\). so sum=\(1 + 2 + 5 + 10 = 18\).
Try this beautiful problem from PRMO, 2019 based on Good numbers.
A natural number \(k > \) is called good if there exist natural numbers
\(a_1 < a_2 < ………. < a_k\)
\(\frac{1}{\sqrt a_1} +\frac{1}{\sqrt a_2}+................... +\frac{1}{\sqrt a_k}=1\)
Let \(f(n)\) be the sum of the first \(n\) good numbers, \(n \geq 1\). Find the sum of all values of \(n\) for which
\(f(n + 5)/f(n)\) is an integer.
Number theory
Good number
Integer
But try the problem first...
Answer:\(18\)
PRMO-2019, Problem 12
Pre College Mathematics
First hint
A number n is called a good number if It is a square free number.
Let \(a_1 ={A_1}^2\),\(a_2={A_2}^2\),..................\(a_k={A_k}^2\)
we have to check if it is possible for distinct natural number \(A_1, A_2………….A_k\) to satisfy,
\(\frac{1}{A_1}+\frac{1}{A_2}+...........+\frac{1}{A_k}=1\)
Can you now finish the problem ..........
Second Hint
For \(k = 2\); it is obvious that there do not exist distinct\( A_1, A_2\), such that \(\frac{1}{A_1}+\frac{1}{A_2}=1 \Rightarrow 2\) is not a good number
For \(k = 3\); we have \(\frac{1}{2} +\frac{1}{3}+\frac{1}{6}=1 \Rightarrow 3\) is a good number.
\(\frac{1}{2}+\frac{1}{2}\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=1\) \(\Rightarrow 4\) is a good number
Let \(k\) wil be a good numbers for all \(k \geq 3\)
\(f(n) = 3 + 4 +… n\) terms =\(\frac{n(n + 5)}{2}\)
\(f(n + 5) =\frac{(n + 5)(n +10)}{2}\)
\(\frac{f(n+5}{f(n)}=\frac{n+10}{n}=1+\frac{10}{n}\)
Can you finish the problem........
Final Step
Therefore the integer for n = \(1\), \(2\), \(5\) and \(10\). so sum=\(1 + 2 + 5 + 10 = 18\).
noice