Try this beautiful problem from Pre RMO, 2019 based on **Geometry and Trigonometry**.

## Geometry and Trigonometry – PRMO 2019

How many distinct triangles ABC are there, up to similarity, such that the magnitudes of angle A, B and C in degrees are positive integers and satisfy cosAcosB + sinAsinBsinkC=1 for some positive integer k, where kC does not exceed 360 degrees.

- is 13
- is 25
- is 6
- cannot be determined from the given information

**Key Concepts**

Geometry

Trigonometry

Number Theory

## Check the Answer

But try the problem first…

Answer: is 6.

PRMO, 2019

Plane Trigonometry by Loney

## Try with Hints

First hint

Here cosAcosB+sinAsinBsinkC=1 then cosAcosB+sinAsinB+sinAsinBsinkC-sinAsinB=1 then sinAsinB(sinkC-1)=1-cos(A-B)

Second Hint

Then sinkC-1=0 and cos(A-B)=1 then kC=90 and A=B

Final Step

Then Number of factors of 90 is 90=(2)(\(3^{2}\))(5) then number of factors=(2)(3)(2)=12 for 6 factor A,B are integers

Google