Try this beautiful problem from Pre RMO, 2019 based on Geometry and Trigonometry.
How many distinct triangles ABC are there, up to similarity, such that the magnitudes of angle A, B and C in degrees are positive integers and satisfy cosAcosB + sinAsinBsinkC=1 for some positive integer k, where kC does not exceed 360 degrees.
Geometry
Trigonometry
Number Theory
But try the problem first...
Answer: is 6.
PRMO, 2019
Plane Trigonometry by Loney
First hint
Here cosAcosB+sinAsinBsinkC=1 then cosAcosB+sinAsinB+sinAsinBsinkC-sinAsinB=1 then sinAsinB(sinkC-1)=1-cos(A-B)
Second Hint
Then sinkC-1=0 and cos(A-B)=1 then kC=90 and A=B
Final Step
Then Number of factors of 90 is 90=(2)(\(3^{2}\))(5) then number of factors=(2)(3)(2)=12 for 6 factor A,B are integers
Try this beautiful problem from Pre RMO, 2019 based on Geometry and Trigonometry.
How many distinct triangles ABC are there, up to similarity, such that the magnitudes of angle A, B and C in degrees are positive integers and satisfy cosAcosB + sinAsinBsinkC=1 for some positive integer k, where kC does not exceed 360 degrees.
Geometry
Trigonometry
Number Theory
But try the problem first...
Answer: is 6.
PRMO, 2019
Plane Trigonometry by Loney
First hint
Here cosAcosB+sinAsinBsinkC=1 then cosAcosB+sinAsinB+sinAsinBsinkC-sinAsinB=1 then sinAsinB(sinkC-1)=1-cos(A-B)
Second Hint
Then sinkC-1=0 and cos(A-B)=1 then kC=90 and A=B
Final Step
Then Number of factors of 90 is 90=(2)(\(3^{2}\))(5) then number of factors=(2)(3)(2)=12 for 6 factor A,B are integers