## What are we learning ?

**Competency in Focus:** Divisibility.

This problem from American Mathematics contest (AMC 8, 2016) is based on the concept of divisibility .## First look at the knowledge graph.

**Next understand the problem**

The number $N$ is a two-digit number. • When $N$ is divided by $9$, the remainder is $1$. • When $N$ is divided by $10$, the remainder is $3$. What is the remainder when $N$ is divided by $11$? $\textbf{(A) }0\qquad\textbf{(B) }2\qquad\textbf{(C) }4\qquad\textbf{(D) }5\qquad \textbf{(E) }7$

##### Source of the problem

American Mathematical Contest 2016, AMC 8 Problem 5

##### Key Competency

### Divisibility

##### Difficulty Level

4/10

##### Suggested Book

**Start with hints**

Do you really need a hint? Try it first!

When $N$ is divided by $10$ it leaves remainder $3$ i.e., $N=10\times P+3 \textbf{ ,where } P$ is an integer. i.e., The unit digit of $N$ must be $3$ because unit digit of $10P$ is zero.

$N$ leaves remainder $1$ when divided by $9$. i.e., $N=9\times Q+1$ where $Q$ is an integer. Since $10\times P+3=9\times Q+1$ the unit digit of $9\times Q +1 $ must be $3$.

Since $N$ is a two digit number then the only possibility is $Q=8$ i.e., $N=9\times 8+1=73$

## AMC - AIME Program

AMC - AIME - USAMO Boot Camp for brilliant students. Use our exclusive one-on-one plus group class system to prepare for Math Olympiad

Google