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# Digits of number | PRMO 2018 | Question 3

Try this beautiful problem from the PRMO, 2018 based on Digits of number.

## Digits of number - PRMO 2018

Consider all 6-digit numbers of the form abccba where b is odd. Determine the number of all such 6-digit numbers that are divisible by 7.

• is 107
• is 70
• is 840
• cannot be determined from the given information

Algebra

Numbers

Multiples

## Check the Answer

PRMO, 2018, Question 3

Higher Algebra by Hall and Knight

## Try with Hints

First hint

abccba (b is odd)

=a($10^5$+1)+b($10^4$+10)+c($10^3$+$10^2$)

=a(1001-1)100+a+10b(1001)+(100)(11)c

=(7.11.13.100)a-99a+10b(7.11.13)+(98+2)(11)c

=7p+(c-a) where p is an integer

Second Hint

Now if c-a is a multiple of 7

c-a=7,0,-7

hence number of ordered pairs of (a,c) is 14

Final Step

since b is odd

number of such number=$14 \times 5$=70.

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Try this beautiful problem from the PRMO, 2018 based on Digits of number.

## Digits of number - PRMO 2018

Consider all 6-digit numbers of the form abccba where b is odd. Determine the number of all such 6-digit numbers that are divisible by 7.

• is 107
• is 70
• is 840
• cannot be determined from the given information

Algebra

Numbers

Multiples

## Check the Answer

PRMO, 2018, Question 3

Higher Algebra by Hall and Knight

## Try with Hints

First hint

abccba (b is odd)

=a($10^5$+1)+b($10^4$+10)+c($10^3$+$10^2$)

=a(1001-1)100+a+10b(1001)+(100)(11)c

=(7.11.13.100)a-99a+10b(7.11.13)+(98+2)(11)c

=7p+(c-a) where p is an integer

Second Hint

Now if c-a is a multiple of 7

c-a=7,0,-7

hence number of ordered pairs of (a,c) is 14

Final Step

since b is odd

number of such number=$14 \times 5$=70.

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