INTRODUCING 5 - days-a-week problem solving session for Math Olympiad and ISI Entrance. Learn More

# Crease of a square paper

A square sheet of paper ABCD is so folded that B falls on the mid-point of M of CD. Prove that the crease will divide BC in the ratio 5:3.

Discussion:

Assuming the side of the square is 's'. Let a part of the crease be 'x' (hence the remaining part is 's-x'). We apply Pythagoras Theorem we solve for x:

$x^2 + \frac {s^2 }{4} = (s-x)^2$ implies $x = \frac {3s}{8}$ and $s-x = \frac {5s}{8}$

Hence the ratio is 5:3.

## Some Useful Links:

### One comment on “Crease of a square paper”

1. […] Discussion […]

This site uses Akismet to reduce spam. Learn how your comment data is processed.

### Cheenta. Passion for Mathematics

Advanced Mathematical Science. Taught by olympians, researchers and true masters of the subject.
HALL OF FAMESUPER STARSBOSE OLYMPIADBLOG
CAREERTEAM
support@cheenta.com