Let n = 51! + 1. Then the number of primes among n+1, n+2, … , n+50 is

(A) 0;

(B) 1;

(C) 2;

(D) more than 2;

**Discussion:**

51! is divisible by 2, 3,… 51.

Hence 51! +2 is divisible by 2, … , 51! + k is divisible by k if

Therefore all of these numbers are composite (none of them are primes).

**Answer is (A) **

*Note: The above problem can be further extended to say that for any natural number of n, we can have n consecutive composite numbers.*