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A conveyor belt having a length (l) and carrying a block of mass (m)
moves at a velocity (v). Determine the distance covered by the block before it stops.

Discussion:

The initial velocity of the block relative to the ground is determined from the conditions $$v_0=at$$ $$l=v_0t-at^2/2$$
Now, acceleration of the block due to friction $$a=\mu g$$
Hence, $$v_0=\sqrt{2\mu gl}$$
The time of the motion of the block along the conveyor belt $$t=\sqrt{\frac{2l}{\mu g}}$$
The distance covered by the block before it stops $$s=l+vt=l+v\sqrt{\frac{2l}{\mu g}}$$