• LOGIN
  • No products in the cart.

Profile Photo

Angular Velocity

A child is pushing a merry-go-round. The angle through which the merry-go-round has turned varies with time according to $$\theta(t)=\gamma t+\beta t^3$$ where \(\gamma=0.4rad/s\) and \(\beta=0.0120 rad/s^3\). What is the initial value of the angular velocity?
Discussion:

The angle through which the merry-go-round has turned varies with time according to $$\theta(t)=\gamma t+\beta t^3$$ where \(\gamma=0.4rad/s\) and \(\beta=0.0120 rad/s^3\).

$$ \omega=\frac{d\theta}{dt}$$

At \(t=0\) $$ \omega=\gamma=0.4 rad/s$$

No comments, be the first one to comment !

Leave a Reply

Your email address will not be published. Required fields are marked *

© Cheenta 2017

Login

Register

FACEBOOKGOOGLE Create an Account
Create an Account Back to login/register
X