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Average and Integers | PRMO 2017 | Question 15

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Try this beautiful problem from the Pre-RMO, 2017 based on Average and Integers.

Average and Integer - PRMO 2017

Integers 1,2,3,....,n where n>2, are written on a board. Two numbers m,k such that 1<m<n,1<k<n are removed and the average of the remaining numbers is found to be 17, find the maximum sum of the two removed numbers.

  • is 107
  • is 51
  • is 840
  • cannot be determined from the given information

Key Concepts




Check the Answer

Answer: is 51.

PRMO, 2017, Question 15

Elementary Algebra by Hall and Knight

Try with Hints


\(\Rightarrow \frac{n^{2}+n-4n+2}{2(n-2)}<17<\frac{n^{2}+n+6}{2(n-2)}\)

\(\Rightarrow \frac{n-1}{2}<17<\frac{n+3}{2}\)

\(\Rightarrow n<35 and n>31\)

\(\Rightarrow\) n=32,33,34

First case n=32 \(\frac{\frac{n(n+1)}{2}-p}{(n+2)}\)=17

\(\Rightarrow\) p=18

Second case, n=33 \(\Rightarrow\) p=34

Third case, n=34 \(\Rightarrow\) p=51.

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