Join the diagonals of the smaller square (i.e GEHF)

Can you now finish the problem ..........

The circle's shaded area is the area of the smaller square(i.e. GEHF) subtracted from the area of the circle

and The area between the two squares is Area of the square ABCD - Area of the square EFGH

can you finish the problem........

Given that the Radius of the circle with centre O is 1.Therefore The area of the circle is \(\pi (1)^2\)=\(\pi\) sq.unit

The diameter of the circle is 2 i.e \(EF=BC=2\) unit

The area of the big square i.e \(ABCD=2^2=4\) sq.unit

\(OE=OH=1\) i.e \(EH=\sqrt{(1^2+1^2)}=\sqrt 2\)

Therefore the area of the smaller square is \((\sqrt 2)^2=2\)

The circle's shaded area is the area of the smaller square(i.e. GEHF) subtracted from the area of the circle =\(\pi\) - 2

The area between the two squares is Area of the square ABCD - Area of the square EFGH=4-2=2 sq.unit

The ratio of the circle's shaded area to the area between the two squares is \( \frac{\pi - 2}{2} \approx \frac{3.14-2}{2} = \frac{1.14}{2} \approx \frac{1}{2}\)