Select Page

An airplane propeller is rotating at $1900$rpm (rev/min).

(a)Compute the propeller’s angular velocity in rad/s.

(b) How many seconds does it take for the propeller to run through $35^\circ$?

Solution:

An airplane propeller is rotating at $1900$rpm (rev/min).

$1$rpm = $2\pi /60$$$\omega=(1900)(2\pi /60)=199$$Hence, the propeller’s angular velocity $\omega$=$199$rad/s.

b) $35^\circ$$\pi/180^\circ$=$0.611$rad.

Since angular velocity $\omega$=199rad/s, the time required for the propeller to run through $35^\circ$=$$\frac{0.611}{199}=3.1\times10^{-3}s$$