An airplane propeller is rotating at \(1900\)rpm (rev/min).

(a)Compute the propeller’s angular velocity in rad/s.

(b) How many seconds does it take for the propeller to run through \(35^\circ\)?

**Solution:**

An airplane propeller is rotating at \(1900\)rpm (rev/min).

\(1\)rpm = \(2\pi /60\)$$ \omega=(1900)(2\pi /60)=199 $$Hence, the propeller’s angular velocity \(\omega\)=\(199\)rad/s.

b) \(35^\circ\)\(\pi/180^\circ\)=\(0.611\)rad.

Since angular velocity \(\omega\)=199rad/s, the time required for the propeller to run through \(35^\circ\)=$$ \frac{0.611}{199}=3.1\times10^{-3}s$$

*Related*