An ice skater spins at \(4\pi \)rad/s with her arms extended. If her moment of inertia with arms folded is \(80\%\) of that with her arms extended, what is her angular velocity when she folded her arms?

**Discussion:**

Conservation of angular momentum gives $$ I_1\omega_1=I_2 \omega_2$$

$$ (I_1) (4\pi)=0.8 I_1 \omega_2

$$

Hence, \(\omega_2=5\pi\)

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