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# AMC 8 2020 Problem 7 | Counting Problem

Try this beautiful Problem based on combinatorics from AMC 8 2020.

## Counting Problem - AMC 8 2020 Problem 7

How many integers between 2020 and 2400 have four distinct digits arranged in increasing order? (For example, 2347 is one integer.

• 9
• 10
• 15
• 21
• 28

Combinatorics

Counting

## Suggested Book | Source | Answer

AMC 8 2020 Problem 7

15

## Try with Hints

The second digit can't be 1 or 2, since the digit need to be increasing and distinct , and the second digit can't be 4 also since the number need to be less than 2400, so its 3

now we need to choose the last two digit from the set $\{4,5,6,7,8,9\}$

now we can do it in $6C2= 15$ ways. now in only one way we can order so there are 15 numbers.

AMC-AIME Program at Cheenta

## Subscribe to Cheenta at Youtube

Try this beautiful Problem based on combinatorics from AMC 8 2020.

## Counting Problem - AMC 8 2020 Problem 7

How many integers between 2020 and 2400 have four distinct digits arranged in increasing order? (For example, 2347 is one integer.

• 9
• 10
• 15
• 21
• 28

Combinatorics

Counting

## Suggested Book | Source | Answer

AMC 8 2020 Problem 7

15

## Try with Hints

The second digit can't be 1 or 2, since the digit need to be increasing and distinct , and the second digit can't be 4 also since the number need to be less than 2400, so its 3

now we need to choose the last two digit from the set $\{4,5,6,7,8,9\}$

now we can do it in $6C2= 15$ ways. now in only one way we can order so there are 15 numbers.

AMC-AIME Program at Cheenta

## Subscribe to Cheenta at Youtube

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