Try out this beautiful algebra problem number 2 from AMC 8 2019 based on the Fundamental Theorem of Algebra.

## AMC 8 2019 Problem 20:

How many different real numbers " width="10" height="8"> satisfy the equation

" width="119" height="19">

**Key Concepts**

Algebra

Value

Telescoping

## Check the Answer

Answer: is (D) 4

AMC 8, 2019, Problem 20

## Try with Hints

The given equation is

and that means

Among both cases, if

then,

and that means we have 2 different real numbers that satisfy the equation.

and if we take another case, then

and so,

and that means we have 2 different real numbers in this `case too that satisfy the equation. So total 2+2=4 real numbers that satisfy the equation.

### Other useful links

### Related Program

Cheenta Numerates Program for AMC - AIME

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Try out this beautiful algebra problem number 2 from AMC 8 2019 based on the Fundamental Theorem of Algebra.

## AMC 8 2019 Problem 20:

How many different real numbers " width="10" height="8"> satisfy the equation

" width="119" height="19">

**Key Concepts**

Algebra

Value

Telescoping

## Check the Answer

Answer: is (D) 4

AMC 8, 2019, Problem 20

## Try with Hints

The given equation is

and that means

Among both cases, if

then,

and that means we have 2 different real numbers that satisfy the equation.

and if we take another case, then

and so,

and that means we have 2 different real numbers in this `case too that satisfy the equation. So total 2+2=4 real numbers that satisfy the equation.

### Other useful links

### Related Program

Cheenta Numerates Program for AMC - AIME

### Subscribe to Cheenta at Youtube