How Cheenta works to ensure student success?
Explore the Back-Story

AMC 10A 2021 Problem 14 | Vieta's Formula

Try this beautiful Problem based on Vieta's Formula from AMC 10A, 2021 Problem 14.

Vieta's Formula | AMC 10A 2021, Problem 14


All the roots of the polynomial $z^{6}$-$10 z^{5}$+$A z^{4}$+$B z^{3}$+$C z^{2}$+$D z+16$ are positive integers, possibly repeated. What is the value of $B$ ?

  • -88
  • -80
  • -64
  • -41
  • -40

Key Concepts


Vieta's Formula

Polynomial

Roots of the polynomial

Suggested Book | Source | Answer


Problem-Solving Strategies by Arthur Engel

AMC 10A 2021 Problem 14

-88

Try with Hints


Find out the degree of the given polynomial.

We know, Degree of polynomial= Number of roots of that polynomial.

Apply Vieta's Formula on the given polynomial.

By Vieta's Formula, the sum of the roots is 10 and product of the roots is 16.

Since there are 6 roots for this polynomial. By trial and check method find the roots.

The roots should be $2, 2, 2, 2, 1, 1$.

Now using the roots reconstruct the polynomial.

So the polynomial should be -

$(z-1)^{2}(z-2)^{4}$

$=(z^{2}-2 z+1)\\(z^{4}-8 z^{3}+24 z^{2}-32 z+16)$

Now equate it with the given polynomial to find the value of $B.$

AMC - AIME Program at Cheenta

Subscribe to Cheenta at Youtube


Try this beautiful Problem based on Vieta's Formula from AMC 10A, 2021 Problem 14.

Vieta's Formula | AMC 10A 2021, Problem 14


All the roots of the polynomial $z^{6}$-$10 z^{5}$+$A z^{4}$+$B z^{3}$+$C z^{2}$+$D z+16$ are positive integers, possibly repeated. What is the value of $B$ ?

  • -88
  • -80
  • -64
  • -41
  • -40

Key Concepts


Vieta's Formula

Polynomial

Roots of the polynomial

Suggested Book | Source | Answer


Problem-Solving Strategies by Arthur Engel

AMC 10A 2021 Problem 14

-88

Try with Hints


Find out the degree of the given polynomial.

We know, Degree of polynomial= Number of roots of that polynomial.

Apply Vieta's Formula on the given polynomial.

By Vieta's Formula, the sum of the roots is 10 and product of the roots is 16.

Since there are 6 roots for this polynomial. By trial and check method find the roots.

The roots should be $2, 2, 2, 2, 1, 1$.

Now using the roots reconstruct the polynomial.

So the polynomial should be -

$(z-1)^{2}(z-2)^{4}$

$=(z^{2}-2 z+1)\\(z^{4}-8 z^{3}+24 z^{2}-32 z+16)$

Now equate it with the given polynomial to find the value of $B.$

AMC - AIME Program at Cheenta

Subscribe to Cheenta at Youtube


Leave a Reply

This site uses Akismet to reduce spam. Learn how your comment data is processed.

Knowledge Partner

Cheenta is a knowledge partner of Aditya Birla Education Academy
Cheenta

Cheenta Academy

Aditya Birla Education Academy

Aditya Birla Education Academy

Cheenta. Passion for Mathematics

Advanced Mathematical Science. Taught by olympians, researchers and true masters of the subject.
JOIN TRIAL
support@cheenta.com
Menu
Trial
Whatsapp
Math Olympiad Program
magic-wandrockethighlight