In a circle, AB be the diameter.. X is an external point. Using straight edge construct a perpendicular to AB from X
If X is inside the circle then how can this be done
Discussion:
Teacher: What fascinates me about CMI problems is that they are at once fundamental and beautiful in nature. This problem which concerns straight edge construction breaths on a very simple geometric fact: you cannot create a right angle with straight edge until it is already there. Try using this hint.
Student: What is a straight edge? Is it a ruler?
Teacher: A straight is a ruler without markings. When you are constructing with straight edge, you are basically allowed to join given points and nothing else. Although another thing that you can do is select new points from the plane.
Student: Since I cannot think of doing anything in particular, let me join XA and XB.
Teacher: That is indeed the first step. Can you think of finding a right angle anywhere? Remember AB is a diameter.
Student: Oh! I see this. Suppose XA and XB intersects the circle at P and Q. $latex \angle APB $ and $latex \angle BQA $ are right angles (as AB is the diameter and these are angles subtended by diameter at the circumference, it is common geometric fact that they must be right angles).
Teacher: Excellent. Suppose AP and BQ intersect at H. Now finish this of.
Student: Sure. Here H is the orthocenter of triangle AXB. Sure the line XH (when produced) will be perpendicular to AB as well (as altitudes of a triangle are concurrent).
The second part of the problem can be done similarly. Here is a diagram that will be 'proof without words'.
Teacher: Very well. CMI 2014 also had a problem on straight edge construction. In fact there is this famed theorem (due to Mohr- Mascheroni) that every construction that can be done by compass and straight edge can be done by a compass alone and (more importantly), any construction doable by a compass can be done by straight provided you have a circle given.
Student: Where can I learn more about this stuff?
Teacher: There is an excellent book from Little Mathematical Library on Geometric Constructions with Compasses Only. You may read it. Soviet Union made some of the best books on olympiad mathematics. Such books and passion is long gone forgotten. Most books that we have now are, sadly speaking, mere manuals of techniques and strategies.

In 2025, 8 students from Cheenta Academy cracked the prestigious Regional Math Olympiad. In this post, we will share some of their success stories and learning strategies. The Regional Mathematics Olympiad (RMO) and the Indian National Mathematics Olympiad (INMO) are two most important mathematics contests in India.These two contests are for the students who are […]

Cheenta Academy proudly celebrates the success of 27 current and former students who qualified for the Indian Olympiad Qualifier in Mathematics (IOQM) 2025, advancing to the next stage — RMO. This accomplishment highlights their perseverance and Cheenta’s ongoing mission to nurture mathematical excellence and research-oriented learning.

Cheenta students shine at the Purple Comet Math Meet 2025 organized by Titu Andreescu and Jonathan Kanewith top national and global ranks.

Celebrate the success of Cheenta students in the Stanford Math Tournament. The Unified Vectors team achieved Top 20 in the Team Round.
[…] Straight Edge Construction Problem (CMI 2015 solution) […]
are sir... khubi soja problem die6e to.