Two blocks of masses \(4kg\) and \(8kg\) are connected by a string and slide down a \(30^\circ\) inclined plane. The coefficient of kinetic friction between the \(4Kg\) block and the plane is \(0.25\); that between the \(8Kg\) block and the plane is \(0.35\).

(a) Calculate the acceleration of each block.

(b) Calculate the tension in the string.

**Discussion:**

Since the larger block has the larger coefficient of friction it will need to be pulled down the plane.

For the small block, $$ 4(sin30^\circ-(0.25)cos30^\circ)-T=4a$$

$$\Rightarrow 4a=11.11N-t$$

For larger block, $$ 15.44+T=8a$$

Now, adding the two relations $$ 26.55N=12a$$

$$ a=2.21m/s^2$$

We can find the tension \(T=2.27N\)