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AIME I Algebra Arithmetic Math Olympiad USA Math Olympiad

Trigonometry and greatest integer | AIME I, 1997 | Question 11

Try this beautiful problem from the American Invitational Mathematics Examination I, AIME I, 1997 based on Trigonometry and greatest integer.

Try this beautiful problem from the American Invitational Mathematics Examination I, AIME I, 1997 based on Trigonometry and greatest integer.

Trigonometry and greatest integer – AIME I, 1997


Let x=\(\frac{\displaystyle\sum_{n=1}^{44}cos n}{\displaystyle\sum_{n=1}^{44}sin n}\), find greatest integer that does not exceed 100x.

  • is 107
  • is 241
  • is 840
  • cannot be determined from the given information

Key Concepts


Trigonometry

Greatest Integer

Algebra

Check the Answer


But try the problem first…

Answer: is 241.

Source
Suggested Reading

AIME I, 1997, Question 11

Plane Trigonometry by Loney

Try with Hints


First hint

here \(\displaystyle\sum_{n=1}^{44}cosn+\displaystyle\sum_{n=1}^{44}sin n\)

=\(\displaystyle\sum_{n=1}^{44}sinn+\displaystyle\sum_{n=1}^{44}sin(90-n)\)

=\(2^\frac{1}{2}\displaystyle\sum_{n=1}^{44}cos(45-n)\)

=\(2^\frac{1}{2}\displaystyle\sum_{n=1}^{44}cosn\)

Second Hint

\(\displaystyle\sum_{n=1}^{44}sin n=(2^\frac{1}{2}-1)\displaystyle\sum_{n=1}^{44}cosn\)

\(\Rightarrow x=\frac{1}{2^\frac{1}{2}-1}\)

\(\Rightarrow x= 2^\frac{1}{2}+1\)

Final Step

\(\Rightarrow 100x=(100)(2^\frac{1}{2}+1)\)=241.

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