Select Page

Akash Singha Roy

Problem:

Number of divisors of $2700$

Solution:

$2700 = 2^2 \times 3^3\times 5^2$

Hence, any divisor of $2700$ must be of the form $2^{a_1} \times 3^{a_2} \times 5^{a_3}$ where $0<=a_1<=2, 0<=a_2<=3, 0<=a_3<=2$

Therefore, by the Multiplication Principle of Counting, the number of divisors of $2700 = (2+1) \times (3+1)\times (2+1) = 36$