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# TIFR 2017 Math Solution -Set of Nilpotent Matrices

TIFR 2017 Math Solution is a part of TIFR entrance preparation series. The Tata Institute of Fundamental Research is India's premier institution for advanced research in Mathematics. The Institute runs a graduate programme leading to the award of Ph.D., Integrated M.Sc.-Ph.D. as well as M.Sc. degree in certain subjects.
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## Problem:State True or False

The set of nilpotent matrices of ( M_3 (\mathbb{R} ) ) spans ( M_3 (\mathbb{R} ) ) considered as an ( \mathbb {R} ) - vector space ( a matrix A is said to be nilpotent if there exists ( n \in \mathbb{N} )  such that ( A^n = 0 ) ).

## Discussion

If such a basis exist. Then it will contain 9 matrices (because dimension of ( M_3 ( \mathbb{R} ) ) is 9 ).

Suppose ( { N_1, ... , N_9 } ) be the 9 nilpotent matrices which span ( M_3 (\mathbb{R} ) ). Now consider the usual basis of ( M_3 (\mathbb{R} ) ) :

$$M_1 = \begin{bmatrix} 1 & 0 & 0 \ 0 & 0 & 0 \ 0 & 0 & 0 \end{bmatrix} , M_2 = \begin{bmatrix} 0 & 1 & 0 \ 0 & 0 & 0 \ 0 & 0 & 0 \end{bmatrix} , ... , M_9 = \begin{bmatrix} 0 & 0 & 0 \ 0 & 0 & 0 \ 0 & 0 & 1 \end{bmatrix}$$

There is a linear transformation L (via a ( 9 \times 9 )  change of basis matrix) that sends ( { N_1, ... , N_9 } ) to ( { M_1, ... , M_9 } ).

## Chatuspathi

• What is this topic: Linear Algebra
• What are some of the associated concept: Eigenvectors,Characteristic Polynomial
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