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# Test of Mathematics Solution Subjective 74 - Sum of Squares of Digits

This is a Test of Mathematics Solution Subjective 74 (from ISI Entrance). The book, Test of Mathematics at 10+2 Level is Published by East West Press. This problem book is indispensable for the preparation of I.S.I. B.Stat and B.Math Entrance.

Also visit: I.S.I. & C.M.I. Entrance Course of Cheenta

## Problem

The sum of squares of the digits of a three-digit  positive number is 146, while the sum of the two digits in the unit's and the ten's place is 4 times the digit in the hundred's place. Further, when the number is written in the reverse order, it is increased by 297. Find the number.

## Solution

Let is unit's digit, is ten's digit and is the hundred's digit.

Then from the given information we get

... (i)
= ...(ii)
= ...(iii)
=
From (iii) we get =
=
Now from (ii) we get

=
=
So b is a multiple of 3, b can be 0, 3, 6, 9.
For b = 0
not possible as
b = 0 a = 1 c = 4
then
Similarly for b = 3 a = 2 c = 5
& b = 6 a = 3 c = 6 are not possible.
For b = 9 a = 4 c = 7

So the only solution is 497.

This is a Test of Mathematics Solution Subjective 74 (from ISI Entrance). The book, Test of Mathematics at 10+2 Level is Published by East West Press. This problem book is indispensable for the preparation of I.S.I. B.Stat and B.Math Entrance.

Also visit: I.S.I. & C.M.I. Entrance Course of Cheenta

## Problem

The sum of squares of the digits of a three-digit  positive number is 146, while the sum of the two digits in the unit's and the ten's place is 4 times the digit in the hundred's place. Further, when the number is written in the reverse order, it is increased by 297. Find the number.

## Solution

Let is unit's digit, is ten's digit and is the hundred's digit.

Then from the given information we get

... (i)
= ...(ii)
= ...(iii)
=
From (iii) we get =
=
Now from (ii) we get

=
=
So b is a multiple of 3, b can be 0, 3, 6, 9.
For b = 0
not possible as
b = 0 a = 1 c = 4
then
Similarly for b = 3 a = 2 c = 5
& b = 6 a = 3 c = 6 are not possible.
For b = 9 a = 4 c = 7

So the only solution is 497.