This is a Test of Mathematics Solution Subjective 127 (from ISI Entrance). The book, Test of Mathematics at 10+2 Level is Published by East West Press. This problem book is indispensable for the preparation of I.S.I. B.Stat and B.Math Entrance.
Find all (x, y) such that sin x + sin y = sin (x+y) and |x| + |y| = 1
|x| + |y| =1 is easier to plot. We have to treat the cases separately.
Now we work on sin x + sin y = sin (x + y).
This implies $ \displaystyle{2 \sin \left ( \frac{x+y} {2} \right ) \cos \left ( \frac{x-y} {2} \right ) = 2 \sin \left ( \frac{x+y} {2} \right ) \cos \left ( \frac{x+y} {2} \right ) }$. Hence we have two possibilities:
The above situations can happen when when
$ \displaystyle{ \frac{x +y}{2} = k \pi } $ or $ \displaystyle{\frac {x}{2} = k \pi }$ or $ \displaystyle{ \frac{y}{2} = k \pi }$, where k is any integer.
Thus we need to plot the class of lines $ \displaystyle{ x + y = 2 k \pi } $, $ \displaystyle{ x = 2k\pi } $ and $ \displaystyle{ y = 2k\pi } $, and consider the intersection points of these lines with the graph of |x| + |y| = 1.
Clearly only for k=0, such intersection points can be found.
Hence required points are (0,1), (0,-1), (1,0), (-1,0), (1/2, -1/2), (-1/2, 1/2).
This is a Test of Mathematics Solution Subjective 127 (from ISI Entrance). The book, Test of Mathematics at 10+2 Level is Published by East West Press. This problem book is indispensable for the preparation of I.S.I. B.Stat and B.Math Entrance.
Find all (x, y) such that sin x + sin y = sin (x+y) and |x| + |y| = 1
|x| + |y| =1 is easier to plot. We have to treat the cases separately.
Now we work on sin x + sin y = sin (x + y).
This implies $ \displaystyle{2 \sin \left ( \frac{x+y} {2} \right ) \cos \left ( \frac{x-y} {2} \right ) = 2 \sin \left ( \frac{x+y} {2} \right ) \cos \left ( \frac{x+y} {2} \right ) }$. Hence we have two possibilities:
The above situations can happen when when
$ \displaystyle{ \frac{x +y}{2} = k \pi } $ or $ \displaystyle{\frac {x}{2} = k \pi }$ or $ \displaystyle{ \frac{y}{2} = k \pi }$, where k is any integer.
Thus we need to plot the class of lines $ \displaystyle{ x + y = 2 k \pi } $, $ \displaystyle{ x = 2k\pi } $ and $ \displaystyle{ y = 2k\pi } $, and consider the intersection points of these lines with the graph of |x| + |y| = 1.
Clearly only for k=0, such intersection points can be found.
Hence required points are (0,1), (0,-1), (1,0), (-1,0), (1/2, -1/2), (-1/2, 1/2).