Sum of whole numbers | AMC-10A, 2012 | Problem 8

Let us assume three numbers are \(x\),\(y\) and \(z\)

Now according to the problem

\(x+y=12\).....................(1)

\(y+z=17\)....................(2)

\(z+x=19\)......................(3).

Can you find out the values of \(x\),\(y\) and \(z\)................?

can you finish the problem........

Adding three equations we get \(2(x=y+z)=48\)

\(\Rightarrow x+y+z=24\).............(3)

Now subtract (3) from (1),we will get \(z=12\) and similarly if we subtract (2) and (3) from (1) we will get \(x=7\) and \(y=5\)

can you finish the problem........

Therefore,the numbers are \(12\), \(7\), and \(5\) and middle number is \(7\)

Let us assume three numbers are \(x\),\(y\) and \(z\)

Now according to the problem

\(x+y=12\).....................(1)

\(y+z=17\)....................(2)

\(z+x=19\)......................(3).

Can you find out the values of \(x\),\(y\) and \(z\)................?

can you finish the problem........

Adding three equations we get \(2(x=y+z)=48\)

\(\Rightarrow x+y+z=24\).............(3)

Now subtract (3) from (1),we will get \(z=12\) and similarly if we subtract (2) and (3) from (1) we will get \(x=7\) and \(y=5\)

can you finish the problem........

Therefore,the numbers are \(12\), \(7\), and \(5\) and middle number is \(7\)