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Try this beautiful problem from the PRMO II, 2019 based on Sum of Digits base 10.

## Sum of Digits base 10 – PRMO II 2019

Let s(n) denote the sum of the digits of a positive integer n in base 10. If s(m)=20 and s(33m)=120, what is the value of s(3m)?

• is 107
• is 60
• is 840
• cannot be determined from the given information

### Key Concepts

Real Numbers

Algebra

Integers

But try the problem first…

Source

PRMO II, 2019, Question 7

Elementary Algebra by Hall and Knight

## Try with Hints

First hint

taking sum of digit base 10 to (mod 9)

and s(ab)=s(a).s(b)(mod 9)

[ let x congruent r mod n, y congruent to s mod n,

$0 \leq r,s \leq n-1$,

x=in+r, y=jn+s, i,j are integers

xy=(in+r)(jn+s)=ij$n^2$+(is+jr)n+rs congruent to rs mod n

so, xy mod n =(x mod n)(y mod n) ]

Second Hint

given s(m)=20

s(33m)=120=$s(11) \times s(3m)$

or, 120=$2 \times s(3m)$ [ since s(11)=2(mod 9)]

Final Step

or, 60=s(3m)

so, s(3m)=60.