Get inspired by the success stories of our students in IIT JAM MS, ISI  MStat, CMI MSc DS.  Learn More 

Shift the Curves | ISI MStat 2019 PSB Problem 1

Join Trial or Access Free Resources

This problem is an easy application in calculus using the basic ideas of curve sketching. This is the problem 1 from ISI MStat 2019 PSB.

Problem- curve sketching

Let \(f(x) = x^{3}-3 x+k,\) where \(k\) is a real number. For what values of
\(k\) will \(f(x)\) have three distinct real roots?



Science is all about asking proper questions. So, \(k\) is the variable here. So, ask the following question,

What role is \(k\) playing here? Let's take \( k = 0\) and see what happens.

\( g(x) = x^{3}- 3x = x(x-\sqrt{3})(x+\sqrt{3})\).

We can easily draw the graph of this \(g(x)\). Let's draw it. So, \(g(x)\) has roots as {\(-\sqrt{3}, 0, \sqrt{3}\)}.

curve sketching

Great, so addding \(k\) to \(g(x)\) will shift the graph upwards right?

curve sketching

Observe that if \(k\) \(\geq\) |lowest value of \(g(x)\) at the bump|, then \(f(x)\) will have less than three roots.

Similarly, observe that if \(k\) \(\leq\) - highest value of \(g(x)\) at the bump, then \(f(x)\) will have less than three roots.

The arrows show the bumps.

So, let's find them out. So, what is the mathematical significance of these bumps? They are the local maximum and minimum. How do we find them?

\(g'(x) = 0\), where \(g(x) = x^{3}- 3x\).

\( \Rightarrow 3x^2 - 3 = 0 \Rightarrow x = \pm 1\).

So, the minimum and the maximum values of \(g(x)\) are \(g(-1) = 2\) and \(g(1) = -2\).

Hence \( -2 < k < 2\).

Let's see what happens at \( k = \pm 2\).

curves on graph

It is just that point, where the transitition for three roots to two roots occur and then to one root.

Observe that since, it is an odd degree, there will always be a reall root of the curve.

Stay Tuned! Stay Blessed!

Food for Thought ( Think with Pictures )

  • \(f(x)\) has \(n\) distinct roots \(\Rightarrow\) \(f'(x)\) has atleast \(n-1\) distinct roots.
  • Is the converse true? i.e. \(f'(x)\) has \(n-1\) distinct roots \(\overset{?}{\Rightarrow}\) \(f(x)\) has atleast \(n\) distinct roots. Can you investigate using the given function?
  • \(f'(x)\) has \(n-1\) distinct roots. Does there exist a \(k\) such that \(f(x)+k\) has atleast \(n\) distinct roots?

Stay Tuned! Stay Blessed!

Leave a Reply

Your email address will not be published. Required fields are marked *

This site uses Akismet to reduce spam. Learn how your comment data is processed.

Knowledge Partner

Cheenta is a knowledge partner of Aditya Birla Education Academy

Cheenta Academy

Aditya Birla Education Academy

Aditya Birla Education Academy

Cheenta. Passion for Mathematics

Advanced Mathematical Science. Taught by olympians, researchers and true masters of the subject.