RMO 2019 solutions with sequential hints

Regional Mathematics Olympiad, India (RMO) 2019… try the problems. We give sequential hints leading up to complete solution. 

Problems in Regional Math Olympiad 2019 (this is being updated continually… stay tuned)

1. Suppose x is a non zero real number such that both \( x^5 \) and \( 20 x + \frac{19}{x} \) are rational numbers. Prove that x is a rational number.  

2. Let ABC be a triangle with circumcircle \( \Omega \) and let G be the centroid of the triangle ABC. Extend AG, BG, and CG to meet \( \Omega \) again at \( A_1, B_1 \) and \(C_1\) respectively. Suppose \( \angle BAC = \angle A_1B_1C_1 , \angle ABC = \angle A_1 C_1 B_1 \) and \( \angle ACB = \angle B_1 A_1 C_1 \). Prove that ABC and \( A_1B_1C_1 \) are equilateral triangles.

3. Let a, b, c be positive real numbers such that a + b + c = 1. Prove that $$ \frac {a} {a^2 + b^3 + c^3} + \frac {b}{ b^2 + c^3 + a^3 } + \frac {c} { c^2 + a^3 + b^3 } \leq \frac{1}{5abc} $$

4. Consider the following \( 3 \times 2 \) array formed by the numbers 1, 2, 3, 4, 5, 6: 

\( \begin{bmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \\ a_{31} & a_{33} \end{bmatrix}  = \begin{bmatrix} 1 & 6 \\ 2 & 5  \\ 3 & 4 \end{bmatrix} \) 

Observe that all row sums are equal, but the sum of the squares in not the same for each row. Extend the above array to a \( 3 \times k \) array \( {a_{(ij)}_{3\times k }  \) for a suitable k adding more columns using the numbers 7, 8, 9, …, 3k such that 

$$ \sum_{j=1}^k a_{1j} = \sum_{j=1}^k a_{2j} = \sum_{j=1}^k a_{3j}, \sum_{j=1}^k (a_{1j})^2 = \sum_{j=1}^k (a_{2j})^2 = \sum_{j=1}^k (a_{3j})^2 $$

5. In an acute angled triangle ABC, let H be the orthocenter, and let D, E, F be the feet of the altitudes from A, B, C to the opposite sides, respectively. Let L, M, N be the midpoints of the segments AH, EF, BC respectively. Let X, Y be feet of altitudes from L, N on to the line DF. Prove that XM is perpendicular to MY.

6. Suppose 91 distinct positive integers greater than 1 are given such that there are atleast 456 pairs among them which are relatively prime. So that one can find four integers a, b, c, d among them such that gcd (a, b) = gcd (b, c) = gcd (c, a) = 1

Maharashtra – Goa Region

Rest of india

One-on-One class for every student!

Group sessions +  24/7 advanced doubt support

What is coming up?

Inequality Module for Math Olympiad

Seminar on how to solve Math Olympiad Problems by Anushka Aggarwal

Faculty panel for Math Olympiad



Director, Faculty Cheenta

Srijit Mukherjee is a B.Stat from Indian Statistical Institute. He is pursuing M.Stat from I.S.I. He is a director and faculty at Cheenta.
Sankhadip Chakraborty

Sankhadip Chakraborty

Faculty, Admin at Cheenta

Sankhadip Chakraborty is an INMO awardee. He has a B.Sc. in Mathematics from CMI and is pursuing Ph.D. at IMPA, Brazil.
Ishan Sengupta

Ishan Sengupta

Faculty at Cheenta

Ishan Sengupta is pursuing B.Stat from Indian Statistical Institute, Kolkata. He is a faculty at Cheenta.
A.R. Sricharan

A.R. Sricharan

Faculty, Cheenta

A.R. Sricharan is a B.Sc. in Mathematics from Chennai Mathematical Institute. He is pursuing M.Sc. from CMI and is a faculty at Cheenta


Try some sequential hints

A trigonometric polynomial ( INMO 2020 Problem 2)

Indian National Math Olympiad (INMO 2020) Solution and sequential hints to problem 2

Kites in Geometry | INMO 2020 Problem 1

Try this beautiful geometry problem from INMO (Indian National Math Olympiad) 2020). We provide solution with sequential hints so that you can try.

Extremal Principle for Counting – AMC 10

Extremal Principle is used in a variety of problems in Math Olympiad. The following problem from AMC 10 is a very nice example of this idea.

Geometry of circles and rectangles AMC 8 2014 problem 20

Try this beautiful problem from AMC 8. It involves geometry of circles and rectangles. We provide sequential hints so that you can try the problem.

Number theory AMC 8 2014 Problem Number 23

Try this beautiful problem from AMC 8. It involves number theory and logical reasoning. We provide sequential hints so that you can try the problem.

Calculating the median of observations AMC 8 2014 Problem 24

Try this beautiful problem from AMC 8. It is based on calculating the median of even number of observations. We provide sequential hints so that you can try the problem.

Geometry of circles in AMC 8 2014 problem 25

Try this beautiful problem from AMC 8. It involves geometry of circles. We provide sequential hints so that you can try the problem.

Beautiful problems from Coordinate Geometry

The following problems are collected from a variety of Math Olympiads and mathematics contests like I.S.I. and C.M.I. Entrances. They can be solved using elementary coordinate geometry and a bit of ingenuity.

Menalaus Theorem in AMC 8 2019

Learn how to use Menalaus’s Theorem to solve geometry problem from AMC 8 2019. We also provide Knowledge Graph and a video discussion.

AMC 8 2019 – Stick and Dot Method

Try this problem from AMC 8 2019 Problem 25. It involved Bijiection Principle from combinatorics, in particular the stick and bar method.

some testimonials.

Jayanta Majumdar, Glasgow, UK

"We contacted Cheenta because our son, Sambuddha (a.k.a. Sam), seemed to have something of a gift in mathematical/logical thinking, and his school curriculum math was way too easy and boring for him. We were overjoyed when Mr Ashani Dasgupta administered an admission test and accepted Sam as a one-to-one student at Cheenta. Ever since it has been an excellent experience and we have nothing but praise for Mr Dasgupta. His enthusiasm for mathematics is infectious, and admirable is the amount of energy and thought he puts into each lesson. He covers a wide range of mathematical topics, and every lesson is packed with insights and methods. We are extremely pleased with the difference he has been making. Under his tutelage Sam has secured several gold awards from the UK Mathematics Trust (UKMT) and Scottish Mathematical Council (SMC). Recently Sam received a book award from the UKMT and got invited to masterclass sessions also organised by the UKMT. Mr Dasgupta's tutoring was crucial for these achievements. We think Cheenta is rendering an excellent service to humanity by identifying young mathematical minds and nurturing them towards becoming inspired mathematicians of the future."

Shubhrangshu Das, Bangalore, India

"My son, Shuborno has been studying under Ashani from last one year. During this period, we have seen our son grow both intellectually and emotionally. His concepts and approach towards solving a problem has become more mature now. Not that he can solve each and every problem but he loves to think on the tough concepts. For this, all credit goes to Ashani, who is never in a hurry to solve a problem quickly. Rather he tries to slowly build the foundation of the students by discussing even minute concepts. His style of teaching is also unique combining different concepts and giving mathematics a more holistic approach. He is also very motivating and helpful. We are lucky that our son is under such good guidance. Rare to get such a dedicated teacher."

Murali Kadaveru, Virginia, USA

"“Our experience with Cheenta has been excellent.  Even though my son started in Middle School, they understood his Math level and took personal interest in developing a long-term plan considering his strengths and weakness areas. Through out the semester courses they have nourished him with challenging problems and necessary homework.  His guidance has helped my son to perform well at competitions including USAJMO and others. He has grown more confident in his math abilities over the past year and half and is hoping to do well in the future.  

I am impressed with their quality and professionalism.  We are very thankful to Cheenta and hope to benefit from them in the coming years.  I would strongly recommend them to any student who wants to learn Math by doing challenging problems, specially if they are looking for Math than what their school can offer.”