INTRODUCING 5 - days-a-week problem solving session for Math Olympiad and ISI Entrance. Learn More 

May 28, 2020

Reflection Problem | AIME I, 1988 | Question 14

Try this beautiful problem from the American Invitational Mathematics Examination I, AIME I, 1988, Question 14, based on Reflection.

Reflection Problem - AIME I, 1988

Let C be the graph of xy=1 and denote by C' the reflection of C in the line y=2x. let the equation of C' be written in the form \(12x^{2}+bxy +cy^{2}+d=0\), find the product bc.

  • is 107
  • is 84
  • is 840
  • cannot be determined from the given information

Key Concepts




Check the Answer

Answer: is 84.

AIME I, 1988, Question 14

Coordinate Geometry by Loney

Try with Hints

First hint

Let P(x,y) on C such that P'(x',y') on C' where both points lie on the line perpendicular to y=2x

slope of PP'=\(\frac{-1}{2}\), then \(\frac{y'-y}{x'-x}\)=\(\frac{-1}{2}\)

or, x'+2y'=x+2y

also midpoint of PP', \((\frac{x+x'}{2},\frac{y+y'}{2})\) lies on y=2x

Second Hint

or, \(\frac{y+y'}{2}=x+x'\)

or, 2x'-y'=y-2x

solving these two equations, x=\(\frac{-3x'+4y'}{5}\) and \(y=\frac{4x'+3y'}{5}\)

putting these points into the equation C \(\frac{(-3x'+4y')(4x'+3y')}{25}\)=1

Final Step

which when expanded becomes


or, bc=(-7)(-12)=84.

Subscribe to Cheenta at Youtube

Leave a Reply

This site uses Akismet to reduce spam. Learn how your comment data is processed.

Cheenta. Passion for Mathematics

Advanced Mathematical Science. Taught by olympians, researchers and true masters of the subject.