Cheenta
How 9 Cheenta students ranked in top 100 in ISI and CMI Entrances?
Learn More

Quadratic equation Problem | AMC-10A, 2002 | Problem 12

Try this beautiful problem from Algebra based Quadratic equation.

Quadratic equation Problem - AMC-10A, 2002- Problem 12


Both roots of the quadratic equation \(x^2 - 63x + k = 0\) are prime numbers. The number of possible values of \(k\) is

  • \(0\)
  • \(1\)
  • \(2\)
  • \(4\)
  • more than \(4\)

Key Concepts


Algebra

Quadratic equation

prime numbers

Check the Answer


Answer: \(1\)

AMC-10A (2002) Problem 12

Pre College Mathematics

Try with Hints


The given equation is \(x^2 - 63x + k = 0\). Say that the roots are primes...

Comparing the equation with \(ax^2 +bx+c=0\) we get \(a=1 , b=-63 , c=k\).. Let \(m_1\) & \(m_2 \) be the roots of the given equation...

using vieta's Formula we may sat that...\(m_1 + m_2 =-(- 63)=63\) and \(m_1 m_2 = k\)

can you finish the problem........

Now the roots are prime. Sum of the two roots are \(63\) and product is \(k\)

Therefore one root must be \(2\) ,otherwise the sum would be even number

can you finish the problem........

So other root will be \(63-2\)=\(61\). Therefore product must be \(m_1m_2=122\)

Hence the answer is \(1\)

Subscribe to Cheenta at Youtube


Knowledge Partner

Cheenta is a knowledge partner of Aditya Birla Education Academy
Cheenta

Cheenta Academy

Aditya Birla Education Academy

Aditya Birla Education Academy

Cheenta. Passion for Mathematics

Advanced Mathematical Science. Taught by olympians, researchers and true masters of the subject.
JOIN TRIAL
support@cheenta.com