How 9 Cheenta students ranked in top 100 in ISI and CMI Entrances?

Learn MoreLet's discuss the problem where we have to find the potential of metal sphere.

**The Problem:**

A metal sphere having a radius (r_1) charged to a potential (\phi_1) is enveloped by a thin-walled conducting spherical shell of radius (r_2). Determine the potential (\phi_2) acquired by the sphere after it has been connected for a short time to the shell by a conductor.

**Solution: **

The charge (q_1) of the sphere can be determined from the relation $$ q_1=4\pi\epsilon_0r_1$$

After the connection of the sphere to the envelope, the entire charge (q_1) will flow from the sphere to the envelope and will be distributed uniformly over its surface.

Its potential (\phi_2) (coinciding with the new value of the potential of the sphere) will be

$$ \phi_2=\frac{q_1}{4\pi\epsilon_0r_2}=\phi_1\frac{r_1}{r_2}$$

Cheenta is a knowledge partner of Aditya Birla Education Academy

Advanced Mathematical Science. Taught by olympians, researchers and true masters of the subject.

JOIN TRIAL