Categories
AMC 10 Math Olympiad USA Math Olympiad

Order Pair | AMC-10B, 2012 | Problem 10

Try this beautiful problem from Algebra, based on Order Pair problem from AMC-10B, 2012. You may use sequential hints to solve the problem

Try this beautiful problem from Algebra: Order Pair

Order Pair – AMC-10B, 2012- Problem 10


How many ordered pairs of positive integers (M,N) satisfy the equation $\frac{M}{6}=\frac{6}{N}$

  • \(31\)
  • \(78\)
  • \(43\)

Key Concepts


Algebra

Order Pair

Multiplication

Check the Answer


Answer: \(78\)

AMC-10A (2010) Problem 21

Pre College Mathematics

Try with Hints


Given that $\frac{M}{6}=\frac{6}{N}$ \(\Rightarrow MN=36\).Next we have to find out the the Possibilities to getting \(a \times b=36\)

can you finish the problem……..

Now the possibilities are ….

$1 \times 36=36$
$2 \times 18=36$
$3 \times 12=36$
$4 \times 9=36$
$6 \times 6=36$

We can reverse the order of the factors for all of the ones listed above, because they are ordered pairs except for 6*6 since it is the same back if you reverse the order.

can you finish the problem……..

Therefore the total Possible order pairs that satisfy the equation $\frac{M}{6}=\frac{6}{N}$=\(9\)

Subscribe to Cheenta at Youtube


Leave a Reply

This site uses Akismet to reduce spam. Learn how your comment data is processed.