# Understand the problem

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# Start with hints

Observe that \( \frac{(x+y)^2 + 3x + y}{2} = \frac{(x+y)^2 + (x+y)}{2} + x\) is the expression what we get after bringing in the symmetry. Now, factorize it and see what we are looking for is \( n = \frac{(x+y)(x+y+1)}{2} + x\). Can you guess anything about the expression \( \frac{(x+y)(x+y+1)}{2} \).

\( \frac{(k)(k+1)}{2} \) is the sum of the first k natural numbers. So, now the idea is that somehow you are taking the first k natural numbers and adding another number x to it to make any number. Can you get the final logic?

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