Problem:

The number of terms in the expression of

[(a+3b)^2 (a-3b)^2]^2

A) 4;

B) 5;

C) 6;

D) 7;

Solution:

[(a+3b)^2 (a-3b)^2]^2

= [\{(a+3b)(a-3b)\}^2]^2

= \{ (a^2 -9b^2)^2\}^2 = (a^2 - 9b^2)^4

By Binomial Theorem, the given expression contains 5 terms (since (x +y)^n has n+1 terms in general).

Answer: B) 5;