# Magnetic Field at Focus of Parabola

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The Problem:

An infinite wire carrying current (I) is bent in the form of a parabola. Find the magnetic field at the focus of the parabola. Take the distance of the focus from the apex as (a).

Solution:

From Biot-Savart law, the magnetic field ar (S) is given by $$\vec{B}= \frac{\mu_0}{4 \pi} \int\frac{I\vec{dl}\times\vec{r}}{r^3}$$
From the figure, we note that
$$|\vec{dl}\times \vec{r}|$$=area of the parallelogram by (\vec{dl}) and (\vec{r}) $$= 2\times1/2\times r.rd\theta$$$$=r^2d\theta$$
Hence, $$\vec{B}=\frac{\mu_0I}{4 \pi}\int_{0}^{2\pi}\frac{d\theta}{r}$$ Using (r(1-cos\theta)=2a) as the equation to the parabola, we get $$\vec{B}=\mu_0I/4a$$

### One comment on “Magnetic Field at Focus of Parabola”

1. Leonardo Gaurav says:

Where is the dl taken??

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