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# Problems of the day

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• #36428
Jatin Kr Dey
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1.  How many positive three-digit integers have a remainder of 2 when divided by 6, a remainder of 5 when divided by 9, and a remainder of 7 when divided by 11 ?

(A) 1 (B) 2 (C) 3 (D) 4 (E) 5                       (AMC)

2.

Suppose $$a ,b , and \ c$$ are nonzero real numbers, and $$a+b+c = 0$$ . What are the possible value(s) for $$\frac{a}{|a|} + \frac{b}{|b|} + \frac{c}{|c|} + \frac{abc}{|abc|}$$? (A) 0 (B) 1,-1 (C)2,-2 (D)0 , 2 and -2 (E) 0 , 1 and -1  (AMC)

• This topic was modified 8 months, 3 weeks ago by Jatin Kr Dey.
• This topic was modified 8 months, 3 weeks ago by Jatin Kr Dey.
• This topic was modified 8 months, 3 weeks ago by Jatin Kr Dey.
• This topic was modified 8 months, 3 weeks ago by Jatin Kr Dey.
#36531
cyberx R3der
Participant

<p style=”text-align: left;”>1) All number of form 198k+194 leave the desired remanider as given for k>=0. So till k=4 u will get 3 digit numbers.therefore the ans is 5.</p>
<p style=”text-align: center;”>2)As the sum of 3 nonzero real numbers is 0.All the no. cant be negative or postive.</p>
Case 1: 1 number negative.(assume a) then abc is also negative. Thus u will get +2 for b and c and -2 for a and abc which equates to 0.

Case 2: 2 numbers negative.(assume a and b) . Then abc is postive. Thus u will get +2 for c and abc and -2 for a and b which equates to 0.

Thus the ans is 0.

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