Double derivative

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  • #66973
    Shreya Nair
    Participant

    Double derivative

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    #67484
    Shirsendu Roy
    Moderator

    It is bounded and converges to 0

    #67620
    Saumik Karfa
    Moderator

    $a^x$ grows in a much faster rate than $x^a$

    after a very big $n$ $e^{\sqrt{n}}$ will be greater than $(n+1)^{100}$ and then it will converge to $0$

    • This reply was modified 4 months, 2 weeks ago by Saumik Karfa.
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