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# Calculus

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• #66014
Shreya Nair
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Calculus

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#66379
Saumik Karfa
Moderator

Solved By : Mr. Aritra Dey (Faculty at Cheenta)

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#66460
Shreya Nair
Participant

See, when $m$ is a point of maxima then $f(m)$ is negative and there is a point $f(a)=0$, then this is a contradiction that maximum value is less than some other value. And the same argument is applicable when $m$ is a point of minima.