Calculus

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  • #66014
    Shreya Nair
    Participant

    Calculus

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    #66379
    Saumik Karfa
    Moderator

    Solved By : Mr. Aritra Dey (Faculty at Cheenta)

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    #66460
    Shreya Nair
    Participant

    Please explain the the contradiction part.

    #66660
    Saumik Karfa
    Moderator

    See, when $m$ is a point of maxima then $f(m)$ is negative and there is a point $f(a)=0$, then this is a contradiction that maximum value is less than some other value. And the same argument is applicable when $m$ is a point of minima.

    And is maxima or minima attends at end points, then maxima = minima

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