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# Flux through A Gaussian Surface

Find the flux through a spherical Gaussian surface of radius (a=1m) surrounding a charge of (8.85pC).

Solution:

The value of (\epsilon_0=8.85*10^{-12})

The flux through the Gaussian surface is the charge (Q) located inside the surface. Therefore, $$\Phi=\frac{Q}{\epsilon_0}$$ $$=8.8510^{-12}/8.8510^{-12}$$ $$=1Nm^2/C$$