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# Flux through A Gaussian Surface

Find the flux through a spherical Gaussian surface of radius $$a=1m$$ surrounding a charge of $$8.85pC$$.

Solution:

The value of $$\epsilon_0=8.85*10^{-12}$$

The flux through the Gaussian surface is the charge $$Q$$ located inside the surface. Therefore, $$\Phi=\frac{Q}{\epsilon_0}$$ $$=8.85*10^{-12}/8.85*10^{-12}$$ $$=1Nm^2/C$$

September 16, 2017